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Sections 1.1 – 1.6: Measurement and Dimensional Anaylsis

Section 1.1: Length

Length is the distance from one end of an object to the other end, or from one object to another. For example, the length of a letter-sized piece of paper is 11 inches. The system for measuring length in the United States is based on the four customary units of length: inch, foot, yard, and mile. You can use any of these four U.S. customary measurement units to describe the length of something, but it makes more sense to use certain units for certain purposes. For example, it makes more sense to describe the length of a rug in feet rather than miles, and to describe a marathon in miles rather than inches.

The table below shows equivalents and conversion factors for the four customary units of measurement of length.

Unit Equivalent Conversion Factor
(longer to shorter)
Conversion Factor
(shorter to longer)
1 foot = 12 inches [latex]\frac{12~inches}{1~foot}[/latex] [latex]\frac{1~foot}{12~inches}[/latex]
1 yard = 3 feet [latex]\frac{3~feet}{1~yard}[/latex] [latex]\frac{1~yard}{3~feet}[/latex]
1 mile = 5280 feet [latex]\frac{5280~feet}{1~mile}[/latex] [latex]\frac{1~mile}{5280~feet}[/latex]

You can use the conversion factors to convert a measurement, such as feet, to another type of measurement, such as inches. Note that each of these conversion factors is a ratio of equal values, so each conversion factor equals 1. Multiplying a measurement by a conversion factor does not change the size of the measurement at all since it is the same as multiplying by 1; it just changes the units that you are using to measure.

There are many more inches for a measurement than there are feet for the same measurement, as feet is a longer unit of measurement. So, you could use the conversion factor [latex]\frac{12~inches}{1~foot}[/latex].

If a length is measured in feet, and you’d like to convert the length to yards, you can think, “I am converting from a shorter unit to a longer one, so the length in yards will be less than the length in feet.” You could use the conversion factor [latex]\frac{1~yard}{3~feet}[/latex].

Dimensional Analysis: The Factor-Label Method

You can use the factor label method to convert a length from one unit of measure to another using the conversion factors. In the factor label method, you multiply by unit fractions to convert a measurement from one unit to another. Study the example below to see how the factor label method can be used to convert a measurement given in feet into an equivalent number of inches.

Example 1

How many inches are in [latex]3\frac{1}{2}[/latex] feet?

Solution: Begin by reasoning about your answer. Since a foot is longer than an inch, this means the answer would be greater than [latex]3\frac{1}{2}[/latex] feet. Now state your givens and your goal.

Given: [latex]3\frac{1}{2}[/latex] feet

Goal: Convert to inches, or equivalently, solve [latex]3\frac{1}{2}[/latex] feet = ________inches

1) Find the conversion factor that compares inches and feet, with “inches” in the
numerator, and multiply.

[latex]3\frac{1}{2}[/latex] feet x [latex]\frac{12~inches}{1 foot}[/latex] = ________inches

2) Rewrite the mixed number as an improper fraction before multiplying.

[latex]\frac{7}{2}[/latex] feet x [latex]\frac{12 inches}{1 foot}[/latex] = ________inches  (Since [latex]3\frac{1}{2}[/latex] = [latex]\frac{7}{2}[/latex])

3) You can cancel similar units when they appear in the numerator and the denominator. So here, cancel the similar units “feet” and “foot.” This eliminates this unit from the problem.

[latex]\frac{7~feet}{2}[/latex] x [latex]\frac{12~inches}{1~foot}[/latex] = [latex]\frac{7~\bcancel{feet}}{2}[/latex]  x [latex]\frac{12~inches}{1~\bcancel{foot}}[/latex] = [latex]\frac{7}{2}[/latex] x [latex]\frac{12~inches}{1}[/latex]

4) Rewrite as multiplication of numerators and denominators. Then divide.

[latex]\frac{7}{2}[/latex]  x [latex]\frac{12~inches}{1}[/latex] = [latex]\frac{7~x~12~inches}{2~x~1}[/latex]  = [latex]\frac{84}{2}[/latex] inches = 42 inches

Answer: [latex]3\frac{1}{2}[/latex] feet equals 42 inches.

Example 2

An interior decorator needs border trim for a home she is wallpapering. She needs 15 feet of border trim for the living room, 30 feet of border trim for the bedroom, and 26 feet of border trim for the dining room. How many yards of border trim does she need?

Solution: State your givens and your goal.

Given: 15 feet of border trim for the living room, 30 feet of border trim for the bedroom, and 26 feet of border trim for the dining room

Goal: How many yards of border trim does she need?

1) You need to find the total length of border trim that is needed for all three rooms in the house. Since the measurements for each room are given in feet, you can add the numbers.

15 feet + 30 feet + 26 feet = 71 feet

2) Observe that our goal is the number of yards, not the number of feet. So we need to convert. How many yards is 71 feet? (Reason about the size of your answer. Since a yard is longer than a foot, there will be fewer yards. Expect your answer to be less than 71.)

71 feet = _____ yards

3) Use the conversion factor [latex]\frac{1~yard}{3~feet}[/latex]

[latex]\frac{71~feet}{1}[/latex] x [latex]\frac{1~yard}{3~feet}[/latex] = _____ yard

4) Since “feet” is in the numerator and denominator, you can cancel this unit. Then rewrite as multiplication of numerators and denominators.

[latex]\frac{71~feet}{1}[/latex] x [latex]\frac{1~yard}{3~feet}[/latex] = [latex]\frac{71~\bcancel{feet}}{1}[/latex] x [latex]\frac{1~yard}{3~\bcancel{feet}}[/latex] = [latex]\frac{71~x~1~yard}{1~x~3}[/latex]

5) Multiply and then rewrite the improper fraction as a mixed number.

[latex]\frac{71~x~1~yard}{1~x~3}[/latex] = [latex]\frac{71}{3}[/latex] yards = [latex]23\frac{2}{3}[/latex]

Answer: The interior designer needs [latex]23\frac{2}{3}[/latex] yards of border trim.

At times, you will need to make unit conversions for measurements in two or three dimensions (think finding an area of a field, or the volume of a container). The following is an example for converting units in two dimensions using an area problem.

Example 3

A landscaper is installing artificial turf for a football field. The dimensions of the football field are 120 yards long by 50 yards wide. His supplier sells artificial turf by the square foot. How many square feet of turf is needed for the field?

Solution: State your givens and your goal.

Given: The dimensions of the football field are 120 yards long by 50 yards wide.

Goal: How many square feet of turf is needed for the field?

1) You need to find the total area of the field that needs to be covered. Since both length and width are given in yards, you can multiply. (Note: The resulting units are in square yards.)

120 yards × 50 yards = 6,000 square yards

2) We are asked to find the number of square feet needed. So convert square yards to  square feet. (Reason about the size of your answer. Since a square foot is smaller than a square yard, there will be more square feet. Expect your answer to be larger than 6000.)

[latex]\frac{6,000~yd^2}{1}[/latex] x [latex]\frac{3~ft}{1~yd}[/latex] x [latex]\frac{3~ft}{1~yd}[/latex] = [latex]\frac{6,000~\bcancel{yd}~\bcancel{yd}}{1}[/latex] x [latex]\frac{3~ft}{1~\bcancel{yd}}[/latex] x [latex]\frac{3~ft}{1~\bcancel{yd}}[/latex] = [latex]\frac{6,000~x~3~ft~x~3~ft}{1~x~1~x~1}[/latex] = 54,000 ft2

Answer: The landscaper needs 54,000 square feet of artificial turf for the football field.

Notice that by using the factor label method you can cancel the units out of the problem, just as if they were numbers. You can only cancel if the unit being cancelled is in both the numerator and denominator of the fractions you are multiplying. In the problem above, you cancelled feet and foot leaving you with inches, which is what you were trying to find.

What if you had used the wrong conversion factor as shown below?

[latex]\frac{7~feet}{2}[/latex]x[latex]\frac{1~foot}{12~inches}[/latex] = ?

You could not cancel the feet because the unit is not the same in both the numerator and the denominator. So if you complete the computation, you would still have both feet and inches in the answer and no conversion would take place.

Section 1.1 You Try Problems:

A) Use the Factor-Label Method to determine the number of feet in [latex]2\frac{1}{2}[/latex] miles.
B) A fence company is measuring a rectangular area in order to install a fence around its perimeter. If the length of the rectangular area is 130 yards and the width is 75 feet, what is the total length of the distance to be fenced?

1.1 – Answers to You Try Problems

a) 13200 feet
b) 930 feet or 310 yards

 

Section 1.2: Weight

You often use the word weight to describe how heavy or light an object or person is. Weight is measured in the U.S. customary system using three units: ounces, pounds, and tons. An ounce is the smallest unit for measuring weight, a pound is a larger unit, and a ton is the largest unit. You can use any of the customary measurement units to describe the weight of something, but it makes more sense to use certain units for certain purposes. For example, it makes more sense to describe the weight of a human being in pounds rather than tons. It makes more sense to describe the weight of a car in tons rather than ounces.

The following table shows the unit conversions and conversion factors that are used to make conversions between customary units of weight.

Unit Equivalents [latex]\frac{Conversion~Factor}{(heavier~to~lighter)}[/latex] [latex]\frac{Conversion~Factor}{(lighter~to~heavier)}[/latex]
1) 1 pound = 16  ounces [latex]\frac{1~pound}{16~ounces}[/latex] [latex]\frac{16~ounces}{1~pound}[/latex]
2) 1 ton = 2000 pounds [latex]\frac{1~ton}{2000~pounds}[/latex] [latex]\frac{2000~pounds}{1~ton}[/latex]

Example 4

A Use the Factor Label Method to determine the number of ounces in [latex]2\frac{1}{4}[/latex] pounds.

Solution: State your givens and your goal.

Given: [latex]2\frac{1}{4}[/latex] pounds

Goal: Determine the equivalent number of ounces

1) Begin by reasoning about your answer. Since a pound is heavier than an ounce, expect your answer to be a number greater than [latex]2\frac{1}{4}[/latex].

[latex]2\frac{1}{4}[/latex] pounds = _______ ounces

2) Multiply by the conversion factor that relates ounces and pounds: [latex]\frac{16~ounces}{1~pound}[/latex]

[latex]2\frac{1}{4}[/latex] pounds x [latex]\frac{16~ounces}{1~pound}[/latex] = _____ ounces

3) Write the mixed number as an improper fraction. The common unit “pound” can be cancelled because it appears in both the numerator and denominator.

[latex]\frac{9~\bcancel{pounds}}{4}[/latex] x [latex]\frac{16~ounces}{1~\bcancel{pound}}[/latex] = _____ ounces

4) Multiply and simplify.

[latex]\frac{9}{4}[/latex] x [latex]\frac{16~ounces}{1}[/latex] = [latex]\frac{9~x~16~ounces}{4~x~1}[/latex] = [latex]\frac{144~ounces}{4}[/latex] = 36 ounces

Answer: There are 36 ounces in [latex]2\frac{1}{4}[/latex] pounds.

There are times when you need to perform calculations on measurements that are given in different units. To solve these problems, you need to convert one of the measurements to the same unit of measurement as the other measurement. Think about whether the unit you are converting to is smaller or larger than the unit you are converting from. This will help you be sure that you are making the right computation. You can use the factor label method to make the conversion from one unit to another.

The following examples require converting between units of weight.

Example 5

A municipal trash facility allows a person to throw away a maximum of 30 pounds of trash per week. Last week, 140 people threw away the maximum allowable trash. How many tons of trash did this equal?

Solution: State your givens and your goal.

Given: maximum of 30 pounds of trash per week per person, 140 people threw away the maximum allowable trash.

Goal: How many tons of trash did this equal?

1) Determine the total trash for the week expressed in pounds. If 140 people each throw away 30 pounds, you can find the total by multiplying.

140 × 30 pounds = 4,200 pounds

2) Then convert 4,200 pounds to tons. Reason about your answer. Since a ton is heavier than a pound, expect your answer to be a number less than 4,200.

4,200 pounds = _____ tons

3) Find the conversion factor appropriate for the situation: [latex]\frac{1~ton}{2000~pounds}[/latex]

[latex]\frac{4200~\bcancel{pounds}}{1}[/latex] x [latex]\frac{1~ton}{2000~\bcancel{pounds}}[/latex] = _____ tons

4) Multiply and simplify. Rewrite your result as a mixed number.

[latex]\frac{4200}{1}[/latex] x [latex]\frac{1~ton}{2000}[/latex] = [latex]\frac{4200~x~1~ton}{1~x~2000}[/latex] = [latex]\frac{4200}{2000}[/latex] tons = [latex]2\frac{1}{10}[/latex] tons

Answer: The total amount of trash generated is [latex]2\frac{1}{10}[/latex] tons.

Example 6

The post office charges $0.44 to mail something that weighs an ounce or less. The charge for each additional ounce, or fraction of an ounce, of weight is $0.17. At this rate, how much will it cost to mail a package that weighs 2 pounds 3 ounces?

Solution: State your givens and your goal.

Given: $0.44 to mail something that weighs an ounce or less, each additional ounce of weight is $0.17

Goal: How much will it cost to mail a package that weighs 2 pounds 3 ounces?

1) Since the pricing is for ounces, convert the weight of the package from pounds and ounces into just ounces.

2 pounds 3 ounces = _____ ounces

2) First use the factor label method to convert 2 pounds to ounces.

[latex]\frac{2~\bcancel{pounds}}{1}[/latex] x [latex]\frac{16~oz}{1~\bcancel{pound}}[/latex] = [latex]\frac{2~x~16}{1}[/latex] oz = 32 oz

3) Add the additional 3 ounces to find the weight of the package.

2 pounds 3 ounces = 32 ounces + 3 ounces = 35 ounces

4) Apply the pricing formula. $0.44 for the first ounce and $0.17 for each additional ounce.

$0.44(1) + $0.17(34) = $0.44 + $5.78 = $6.22

Answer: It will cost $6.22 to mail a package that weighs 2 pounds 3 ounces.

Section 1.2 You Try Problems:

A) How many pounds is 72 ounces?
B) The average weight of a northern Bluefin tuna is 1,800 pounds. The average weight of a great white shark is [latex]2\frac{1}{2}[/latex] tons. On average, how much more does a great white shark weigh, in pounds, than a northern Bluefin tuna?

1.2 – Answers to You Try Problems

a) 4.5 pounds
b) 3200 pounds

 

Section 1.3: Capacity

Capacity is the a mount of liquid (or other pourable substance) that an object ca n hold when it’s full. When a liquid, such as milk, is being described in gallons or quarts, this is a measure of capacity.

There are five main units for measuring capacity in the U.S. customary measurement system. The smallest unit of measurement is a fluid ounce. “Ounce” is also used a s a measure of weight, so it is important to use the word “fluid” with ounce when you are talking a bout capacity. Sometimes the prefix “fluid” is not used when it is clear from the context that the measurement is capacity, not weight. The other units of capacity in the customary system are the cup, pint, quart, and gallon. The table below describes each unit of capacity and provides an example to illustrate the size of the unit of measurement.

You can use any of these five measurement units to describe the capacity of an object, but it makes more sense to use certain units for certain purposes. For example, it makes more sense to describe the capacity of a swimming pool in gallons and the capacity of an expensive perfume in fluid ounces.

The table below shows some of the most common equivalents and conversion factors for the five customary units of measurement of capacity.

Unit Equivalents [latex]\frac{Conversion~Factor}{(more~to~less)}[/latex] [latex]\frac{Conversion~Factor}{(less~to~more)}[/latex]
1 pint = 2 cups [latex]\frac{1~pint}{2~cups}[/latex] [latex]\frac{2~cups}{1~pint}[/latex]
1 quart = 2 pints [latex]\frac{1~quart}{2~pints}[/latex] [latex]\frac{2~pints}{1~quart}[/latex]
1 quart  = 4 cups [latex]\frac{1~quart}{4~cups}[/latex] [latex]\frac{4~cups}{1~quart}[/latex]
1 gallon = 4 quarts [latex]\frac{1~gallon}{4~quarts}[/latex] [latex]\frac{4~quarts}{1~gallon}[/latex]
1 gallon = 16 cups [latex]\frac{1~gallon}{16~cups}[/latex] [latex]\frac{16~cups}{1~gallon}[/latex]

As with converting units of length and weight, you can use the factor label method to convert from one unit of capacity to another.

Example 7

Use the Factor Label Method to determine the number of pints in [latex]2\frac{3}{4}[/latex] gallons.

Solution: State your givens and your goal.

Given: [latex]2\frac{3}{4}[/latex] gallons.

Goal: Find the equivalent amount in pints.

1) Begin by reasoning about your answer. Since a gallon is larger than a pint, expect the answer in pints to be a number greater than [latex]2\frac{3}{4}[/latex].

[latex]2\frac{3}{4}[/latex] gallons = _____ pints

2) The table above does not contain a conversion factor for gallons and pints, so you cannot convert it in one step. However, you can use quarts as an intermediate unit, as shown here. Set up the equation so that two sets of labels cancel gallons and quarts.

[latex]2\frac{3}{4}[/latex] gallons = [latex]\frac{11~\bcancel{gallons}}{4}[/latex] x [latex]\frac{4~\bcancel{quarts}}{1~\bcancel{gallon}}[/latex] x [latex]\frac{2~pints}{1~\bcancel{quart}}[/latex] = [latex]\frac{11~X~4~X~2}{4~X~1~X~1}[/latex] pints = 22 pints

Answer: [latex]2\frac{3}{4}[/latex] gallons is equivalent to 22 pints.

Another way to work the problem above would be to first change 1 gallon to 16 cups and change 2 quarts to 8 cups. Then add: 16 + 8 = 24 cups.

Example 8

Natasha is making lemonade to bring to the beach. She has two containers. One holds one gallon and the other holds 2 quarts. If she fills both containers, how many cups of lemonade will she have?

Solution: State your givens and your goal.

Given: Two containers for lemonade; one holds one gallon and the other holds 2 quarts, fills both containers.

Goal: How many cups of lemonade will she have?

1) This problem requires you to find the sum of the capacity of each container and then convert that sum to cups.

1 gallon + 2 quarts = ___ cups

2) First, find the sum in quarts. 1 gallon is equal to 4 quarts.

4 quarts + 2 quarts = 6 quarts

3) Since the problem asks for the capacity in cups, convert 6 quarts to cups.

[latex]\frac{6~\bcancel{quarts}}{1}[/latex] x [latex]\frac{2~\bcancel{pints}}{1~\bcancel{quart}}[/latex] x [latex]\frac{2~cups}{1~\bcancel{pints}}[/latex] = [latex]\frac{6~X~2~X~2~cups}{1~X~1~X1}[/latex] = 24 cups

Answer: Natasha will have 24 cups of lemonade.

Section 1.3 You Try Problems

Alan is making chili. He is using a recipe that makes 24 cups of chili. He has a 5-quart pot and a 2-gallon pot and is trying to determine whether the chili will all fit in one of these pots. Which of the pots will fit the chili?

A) The chili will not fit into either of the pots.
B) The chili can fit into either pot.
C) The chili will fit into the 5-quart pot only.
D) The chili will fit into the 2-gallon pot only.

1.3 – Answers to You Try Problems

Answer D: The chili will fit into the 2-gallon pot only.

 

Section 1.4: The Metric System

In the United States, both the U.S. customary measurement system and the metric system are used, especially in medical, scientific, and technical fields. In most other countries, the metric system is the primary system of measurement. If you travel to other countries, you will see that road signs list distances in kilometers and milk is sold in liters. People in many countries use words like “kilometer,” “liter,” and “milligram” to measure the length, volume, and weight of different objects. These measurement units are part of the metric system. Unlike the U.S. customary system of measurement, the metric system is based on 10s. For example, a liter is 10 times larger than a deciliter, and a centigram is 10 times larger than a milligram. This idea of “10” is not present in the U.S. customary system—there are 12 inches in a foot, and 3 feet in a yard…and 5,280 feet in a mile! What if you have to find out how many milligrams are in a decigram? Or, what if you want to convert meters to kilometers? Understanding how the metric system works is a good start.

What is Metric?

The metric system uses units such as meter, gram, and liter to measure length, mass, and liquid volume (capacity), just as the U.S. customary system uses feet, ounces, and quarts to measure these. In addition to the difference in the basic units, the metric system is based on 10s, and different measures for length include kilometer, meter, decimeter, centimeter, and millimeter. Notice that the word “meter” is part of all of these units. The metric system also applies the idea that units within the system get larger or smaller by a power of 10. This means that a meter is 100 times larger than a centimeter, and a kilogram is 1,000 times heavier than a gram. You will explore this idea a bit later. For now, notice how this idea of “getting bigger or smaller by 10” is very different than the relationship between units in the U.S. customary system, where 3 feet equals 1 yard, and 16 ounces equals 1 pound.

Length, Mass, and Volume

The table below shows the basic units of the metric system. Note that the names of all metric units follow from these three basic units.

Basic Units of Metric System
Length: Meter (m) Mass: Gram (g) Volume: liter (L)

 

Other Units You May See
kilometer (km) kilogram (kg) dekaliter (dL)
centimeter (cm) centigram (cg) centiliter (cL)
millimeter (mm) milligram (mg) milliliter (mL)

In the metric system, the basic unit of length is the meter. A meter is slightly larger than a yardstick, or just over three feet.

The basic metric unit of mass is the gram. A regular-sized paperclip has a mass of about 1 gram. Among scientists, one gram is defined as the mass of water that would fill a 1-centimeter cube. You may notice that the word “mass” is used here instead of “weight.” In the sciences and technical fields, a distinction is made between weight and mass. Weight is a measure of the pull of gravity on an object. For this reason, an object’s weight would be different if it was weighed on Earth or on the moon because of the difference in the gravitational forces. However, the object’s mass would remain the same in both places because mass measures the amount of substance in an object. As long as you are planning on only measuring objects on Earth, you can use mass/weight fairly interchangeably—but it is worth noting that there is a difference!

Finally, the basic metric unit of volume is the liter. A liter is slightly larger than a quart.

An image depicting a shovel, paperclip, and glass of milk accompanied by measurements of 1 meter, 1 gram, and 1 liter.

Prefixes in the Metric System

The metric system is a base 10 system. This means that each successive unit is 10 times larger than the previous one. The names of metric units are formed by adding a prefix to the basic unit of measurement. To tell how large or small a unit is, you look at the prefix. To tell whether the unit is measuring length, mass, or volume, you look at the base.

Prefixes in the Metric System
kilo- hecto- deka- -meter
-gram
-liter
deci- centi- milli-
1,000 times larger than base unit 100 times larger than base unit 10 times larger than base unit base unit(s) 10 times smaller than base unit 100 times smaller than base unit 1,000 times smaller than base unit

Using this table as a reference, you can see the following:

  • A kilogram is 1,000 times larger than one gram (so 1 kilogram = 1,000 grams).
  • A centimeter is 100 times smaller than one meter (so 1 meter = 100 centimeters).
  • A dekaliter is 10 times larger than one liter (so 1 dekaliter = 10 liters).

Here is a similar table that just shows the metric units of measurement for mass, along with their size relative to 1 gram (the base unit). The common abbreviations for these metric units have been included as well.

    Measuring Mass in the Metric System
kilogram (kg) hectogram (hg) dekagram (dag) gram (g) decigram (dg) centigram (cg) milligram (mg)
1,000 grams 100 grams 10 grams 1 gram 0.1 gram 0.01 gram 0.001 gram

Since the prefixes remain constant through the metric system, you could create similar charts for length and volume. The prefixes have the same meanings whether they are attached to the units of length (meter), mass (gram), or volume (liter).

Converting Within the Metric System

While knowing the different units used in the metric system is important, the real purpose behind learning the metric system is for you to be able to use these measurement units to calculate the size, mass, or volume of different objects. In practice, it is often necessary to convert one metric measurement to another unit—this happens frequently in the medical, scientific, and technical fields, where the metric system is commonly used.

The tables below show some of the unit equivalents for length, mass, and volume in the metric system.

Common Metric Length Conversions
1 centimeter = 10 millimeters 1 cm = 10 mm
1 decimeter = 10 centimeters 1 dm = 10 cm
1 meter = 100 centimeters 1 m = 100 cm
1 kilometer = 1000 meters 1 km = 1000 m
Common Metric Mass Conversions
1 gram = 1000 milligrams 1 g = 1000 mg
1 decagram = 10 grams 1 dag = 10 g
1 kilogram = 1000 grams 1 kg = 1000 g
Common Metric Volume Conversions
1 centiliter = 10 milliliters 1 cl = 10 ml
1 deciliter = 10 centiliters 1 dl = 10 cl
1 liter = 1000 milliliters 1 l = 1000 ml
1 liter = 10 deciliters 1 l = 10 dl
1 kiloliter = 1000 liters 1 kl = 1000 l

Remember that the metric system is based on the notion that each unit is 10 times larger than the one that came before it.

Example 9

Convert 7,225 centimeters to meters.

Solution: State your givens and your goal.

Given: 7,225 centimeters.

Goal: Find the equivalent length in meters.

1) Meters is larger than centimeters, so you expect your answer to be less than 7,225.

7,225 cm = _____ m

2) Using the factor label method, write 7,225 cm as a fraction and use unit fractions to convert it to meters.

[latex]\frac{7,225~cm}{1}[/latex] x [latex]\frac{1~m}{100~cm}[/latex] =  _____ m

3) Cancel similar units, multiply, and simplify.

[latex]\frac{7,225~\bcancel{cm}}{1}[/latex] x [latex]\frac{1~m}{100~\bcancel{cm}}[/latex] = [latex]\frac{7,225~X~1~m}{1~X~100}[/latex] = 72.25 m

Answer: 7,225 centimeters = 72.25 m

Learning how to solve real-world problems using metric conversions is as important as learning how to do the conversions themselves. Mathematicians, scientists, nurses, and even athletes are often confronted with situations where they are presented with information using metric measurements, and must then make informed decisions based on that data.

To solve these problems effectively, you need to understand the context of a problem, perform conversions, and then check the reasonableness of your answer. Do all three of these steps and you will succeed in whatever measurement system you find yourself using.

Example 10

In the Summer Olympic Games, athletes compete in races of the following lengths:100 meters, 200 meters, 400 meters, 800 meters, 1500 meters, 5000 meters and 10,000 meters. If a runner were to run in all these races, how many kilometers would he run?

Solution: State your givens and your goal.

Given: The lengths: 100 meters, 200 meters, 400 meters, 800 meters, 1500 meters, 5000 meters and 10,000 meters.

Goal: If a runner were to run in all these races, how many kilometers would he run?

1) To figure out how many kilometers he would run, you need to first add all of the lengths of the races together and then convert that measurement to kilometers.

100 m + 200 m + 400 m + 800 m + 1500 m + 5000 m + 10,000 m = 18,000 m

2) Use the factor label method and unit fractions to convert from meters to kilometers.

[latex]\frac{18,000~m}{1}[/latex] x [latex]\frac{1~km}{1000~m}[/latex] =  _____ km

3) Cancel common units, multiply, and divide.

[latex]\frac{18,000~\bcancel{m}}{1}[/latex] x [latex]\frac{1~km}{1000~\bcancel{m}}[/latex] = [latex]\frac{18,000~X~1~km}{1~X~1000}[/latex] = 18 km

Answer: The runner would run 18 km.

Example 11

One bottle holds 295 dL while another one holds 28,000 mL. What is the difference in capacity between the two bottles?

Solution: State your givens and your goal.

Given: Two bottle capacities: 295 dL and 28,000 mL.

Goal: What is the difference in capacity between the two bottles?

1) The two measurements are in different units. You can convert both units to liters and then compare them.

295 dL = _____ L [latex]\frac{295~dL}{1}[/latex] x [latex]\frac{1~L}{10~dL}[/latex] = [latex]\frac{295~dL}{10}[/latex] = 29. 5 L
28,000 mL = _____ L [latex]\frac{28,000~mL}{1}[/latex] x [latex]\frac{1~L}{1000~mL}[/latex] = [latex]\frac{28,000~L}{1000}[/latex] = 28 L

2) The question asks for “difference in capacity” between the bottles so we will subtract.

29.5 L – 28 L = 1.5 L

Answer: There is a difference in capacity of 1.5 liters between the two bottles.

Example 12

A two-liter bottle contains 87 centiliters of oil and 4.1 deciliters of water. How much more liquid is needed to fill the bottle?

Solution: State your givens and your goal.

Given: a 2-Liter bottle contains 87 cL of oil and 4.1 dL of water.

Goal: How much more liquid is needed to fill the bottle?

1) You are looking for the amount of liquid needed to fill the bottle. First determine the amount of liquid already in the bottle by convert both measurements to liters and adding.

87 cL = _____ L [latex]\frac{87~cL}{1}[/latex] x [latex]\frac{1~L}{100~cL}[/latex] = [latex]\frac{87~L}{100}[/latex] = 0.87 L
4.1 dl = _____ L [latex]\frac{4.1~dL}{1}[/latex] x [latex]\frac{1~L}{10~dL}[/latex] = [latex]\frac{4.1~L}{10}[/latex] = 0.41 L

Total liquid in bottle: 0.87 L + 0.41 L = 1.28 L

2) Find the difference between 2 L and the amount of liquid in the bottle to see how much more liquid is needed to fill the bottle.

2 L – 1.28 L = 0.72 L

Answer: The amount of liquid needed to fill the bottle is 0.72 liters.

Section 1.4 You Try Problems

A) The distance from Scottsdale to Las Vegas is 421 km.

  • What is the equivalent distance in meters?
  • What is the equivalent distance in centimeters?

B) One boxer weighs in at 85 kg. He is 80 dekagrams heavier than his opponent. How much does his opponent weigh?

1.4 – Answers to You Try Problems

a) 42,100,000 cm, 421,000 m
b) 84.2kg

 

Section 1.5: Converting Between Systems

We have spent the last several sections learning about the U.S. customary system of measurement, and the metric system. As you might guess, there are many applications where it is useful to be able to convert between measurements of length, mass, and volume (capacity) in the two systems. The table below gives some useful conversions between U.S. and metric measurements:

Approximate Conversions between Customary and Metric Systems
Length Mass Volume
1 inch = 2.540 centimeters 1 pound = 0.4536 kilograms 1 fluid ounce = 29.574 milliliters
1 foot = 0.3048 m 1 ounce = 28 grams 1 quart = 0.9464 liters
1 yard = 0.9144 meters <this space intentionally left blank> 1 gallon = 3.785 liters
1 mile = 1.6093 kilometers <this space intentionally left blank> <this space intentionally left blank>

Example 13

An Olympic sprinter competes in the 400m dash. How many yards is the race?

Solution: State your givens and your goal.

Given: 400m dash

Goal: How many yards is the race?

1) Reason about your answer. A yard is less than a meter, so you expect your answer to be more than 400.

400 m = _____ yd

2) Using the factor label method, write 400 m as a fraction and use unit fractions to convert it to yards.

[latex]\frac{400~m}{1}[/latex] x [latex]\frac{0.9144~yd}{1~m}[/latex] = _____ yd

3) Cancel similar units, multiply, and simplify.

[latex]\frac{400~\bcancel{m}}{1}[/latex] x [latex]\frac{0.9144~yd}{1~\bcancel{m}}[/latex] = [latex]\frac{400~X~0.9144~yd}{1~X~1}[/latex] = 437.45 yd

Answer: A 400 m dash is 437.45 yards.

Example 14

A patient must be weighed prior to surgery so that the proper dosage of anesthesia can be given. A nurse weighs a patient and finds that he weighs 205 pounds. The anesthesiologist prefers weights in kilograms. What is the patient’s weight in kilograms? Round
to the nearest hundredth.

Solution: State your givens and your goal.

Given: patient weighs 205 pounds

Goal: What is the patient’s weight in kilograms?

1) Reason about your answer. Pounds are smaller than kilograms, so you expect your answer to be less than 205.

205 pounds = _____ kg

2) Using the factor label method, write 205 lbs. as a fraction and use unit fractions to convert it to kilograms.

[latex]\frac{205~lbs}{1}[/latex] x [latex]\frac{1~kg}{2.2~lbs}[/latex] = _____ kg

3) Cancel similar units, multiply, and simplify.

[latex]\frac{205~\bcancel{lbs}}{1}[/latex] x [latex]\frac{1~kg}{2.2~\bcancel{lbs}}[/latex] = [latex]\frac{205~X~1~kg}{2.2}[/latex] = [latex]\frac{205~kg}{2.2}[/latex] ≈ 93.18 kg

Answer: The patient’s weight is 93.18 kg.

Example 15

Your work is having its annual potluck, and you are asked to bring 5 gallons of lemonade. When you go to the store, each container of lemonade mix says it will make 6 liters. How many containers do you need to buy?

Solution: State your givens and your goal.

Given: Need 5 gallons of lemonade. Lemonade mix says it will make 6 liters.

Goal: How many containers do you need to buy?

1) Convert 5 gallons to liters. Reason about your answer. Liters are smaller than gallons, so you expect your answer to be more than 5.

5 gallons = _____ L

2) Using the factor label method, write 5 gal as a fraction and use unit fractions to convert it to liters. Cancel similar units, multiply, and simplify.

[latex]\frac{5~\bcancel{gallons}}{1}[/latex] x [latex]\frac{3.785~L}{1~\bcancel{gallon}}[/latex] = [latex]\frac{5~X~3.785~L}{1~X~1}[/latex] = 18.925 L

3) You need 18.925 liters, and each container of mix will make 6 liters. Convert to containers.

[latex]\frac{18.925~\bcancel{L}}{1}[/latex] x [latex]\frac{1~container}{6~\bcancel{L}}[/latex] = [latex]\frac{18.925~X~1~container}{6}[/latex] = 3.15 containers

4) Since you cannot buy a partial container, and you want to have enough lemonade, you should buy 4 containers, (3 containers would not be enough)

Answer: You need to buy 4 containers of lemonade.

Temperature Conversions

There are three commonly used systems for measuring temperature. One such system is usually used in science, and is called the Kelvin scale. We will focus our attention on the other two scales for measuring temperature: Fahrenheit and Celsius. The United States usually uses the Fahrenheit system. In this system, water freezes to ice at 32°F and boils at 212°F. Another commonly used temperature scale is the Celsius scale, where water freezes to ice at 0°C and boils at 100°C. You might notice that in the Fahrenheit scale there is a 180 degree difference (212°F ─ 32°F) between the temperature where water boils and freezes, while in the Celsius scale there is a 100 degree difference (100°C ─ 0°C) between the temperature where water boils and freezes. Since neither of these two temperature scales has an absolute starting point (a lowest 21 possible temperature) we cannot meaningfully compare temperatures in these scales using conversion factors.

Instead, we have temperature conversion formulas which allow us to convert temperatures back and forth between Fahrenheit and Celsius.

Convert from Celsius to Fahrenheit: F = 1.8C + 32
Convert from Fahrenheit to Celsius: C = [latex]\frac{F-32}{1.8}[/latex]

Example 16

Your front yard is full of weeds, so you decide to spray it with weed killer. The bottle of weed killer that you purchase says “Do not apply in temperatures below 18°C or above 32°C.” What are the corresponding temperatures in degrees Fahrenheit?

Solution: State your givens and your goal.

Given: Do not apply in temperatures below 18°C or above 32°C

Goal: What are the corresponding temperatures in degrees Fahrenheit?

1) Both temperatures are in degrees Celsius and need to be converted into degrees Fahrenheit. Use F = 1.8C + 32

For C = 18, F = 1.8(18) + 32 = 64.4°F (low temperature)

For C = 32, F = 1.8(32) + 32 = 89.6°F (high temperature)

Answer: The weed killer should only be applied when the temperature is between 64.4°F and 89.6°F.

Example 17

When leaving the hospital with your sick child, you are told to return immediately if her temperature exceeds 101.5°F. When you get home, you discover your thermometer will only measure temperature in degrees Celsius. At what temperature, in degrees Celsius, would
you need to return your child to the hospital?

Solution: State your givens and your goal.

Given: Return immediately if her temperature exceeds 101.5°F

Goal: At what temperature, in degrees Celsius, would you need to return your child to the hospital?

1) The temperature is in degrees Fahrenheit and it needs to be converted into degrees Celsius. Use C = [latex]\frac{F-32}{1.8}[/latex]

For F = 101.5°F, C = [latex]\frac{101.5 - 32}{1.8}[/latex] = [latex]\frac{69.5}{18}[/latex] = 38.61°C

Answer: You need to return your child to the hospital if her temperature exceeds 38.61°C.

Section 1.5 You Try Problem

What was the temperature in degrees Celsius, if the evening news reports that the high temperature in Phoenix, Arizona today was 115°F?

1.5 – Answers to You Try Problems

46.1°C

 

Section 1.6: Problem Solving Using Rates & Dimensional Analysis

A rate is the ratio of two quantities. A unit rate is a rate with a denominator of one.

Example 18

Your car can drive 300 miles on a tank of 15 gallons. Express this as a rate and as a unit rate, in miles per gallon.

Solution: State your givens and your goal.

Given: Your car can drive 300 miles on a tank of 15 gallons.

Goal: Express this as a rate and as a unit rate, in miles per gallon.

1) As a rate, create a fraction with the two quantities with miles in the numerator and gallons in the denominator. Include units in your answer.

[latex]\frac{300~miles}{15~gallons}[/latex]

2) As a unit rate, divide the quantity in the numerator by the quantity in the denominator. Use the “units miles per gallon” (equivalent to miles per 1 gallon).

[latex]\frac{300~miles}{15~gallons}[/latex] = [latex]\frac{300}{15}[/latex] x [latex]\frac{miles}{gallons}[/latex] = 20 miles per gallons

Notice that, had we wanted to find the unit rate in gallons per mile, we would have had to invert the original rate:

[latex]\frac{15~gallons}{300~miles}[/latex] = [latex]\frac{15}{300}[/latex] x [latex]\frac{gallons}{miles}[/latex] = [latex]\frac{1}{20}[/latex] gallons per mile

Example 19

Use the following information to compare the electricity consumption per capita in China to the rate in Japan.

From the CIA1 website we can find the electricity consumption in 2011 for China was 4,693,000,000,000 KWH (kilowatt-hours), or 4.693 trillion KWH, while the consumption for Japan was 859,700,000,000, or 859.7 billion KWH. To find the rate per capita (per person), we will also need the population of the two countries. From the World Bank2, we can find the population of China is 1,344,130,000, and the population of Japan is 127,817,277.

Solution: State your givens and your goal.

Given: China: 4.693 trillion KWH and 1,344,130,000 people. Japan: 859.7 billion KWH
and 127,817,277 people.

Goal: Computing the consumption per capita for each country and compare the results.

1) Find KWH per person for China and Japan by dividing the quantity KWH by the number of people.

China: [latex]\frac{4,693,000,000,000~KWH}{1,344,130,000~people}[/latex] = 3,491.49 KWH per person

Japan: [latex]\frac{859,700,000,000~KWH}{127,817,277~people}[/latex] = 6,726 KWH per person

Answer: While China uses more than 5 times the electricity of Japan overall, because the population of Japan is so much smaller, it turns out Japan uses almost twice the electricity per person compared to China.

Many problems can also be solved by multiplying a quantity by rates to change the units. This is the foundation of the Factor-Label process that we have been using already in this chapter.

Example 20

Your car can drive 300 miles on a tank of 15 gallons. How far can it drive on 40 gallons? How many gallons are needed to drive 50 miles?

Solution: State your givens and your goal.

Given: Your car can drive 300 miles on a tank of 15 gallons.

Goals: a) How far can it drive on 40 gallons? b) How many gallons are needed to drive 50 miles?

a) We found that 300 miles on 15 gallons gives a rate of 20 miles per gallon. If we multiply the given 40 gallon quantity by this rate, the gallons unit “cancels” and we’re left with a number of miles.

[latex]\frac{40~\bcancel{gallons}}{1}[/latex] x [latex]\frac{20~miles}{1~\bcancel{gallon}}[/latex] = [latex]\frac{40~x~20}{1~x~1}[/latex] = 800 miles

b) We also found that 300 miles on 15 gallons gives a rate of [latex]\frac{1}{20}[/latex] gallons per mile. If we multiply the given 50 mile quantity by this rate, the miles unit “cancels” and we’re left with gallons.

[latex]\frac{50~\bcancel{miles}}{1}[/latex] x [latex]\frac{1~gallon}{20~\bcancel{miles}}[/latex] = [latex]\frac{50~x~1}{1~x~20}[/latex] gallons = 2.5 gallons

Answers: The car can drive 800 miles on 40 gallons of gas. The car needs 2.5 gallons of gas to drive 50 miles.

Example 21

A bicycle is traveling at 15 miles per hour. How many feet will it cover in 20 seconds?

Solution: State your givens and your goal.

Given: 15 miles per hour.

Goal: How many feet will the bicycle cover in 20 seconds?

1) To answer this question, we need to convert 20 seconds into feet. If we know the speed of the bicycle in feet per second, this question would be simpler. Since we don’t, we will need to do additional unit conversions. We will need to know that 5280 feet = 1 mile. We might start by converting the 20 seconds into hours:

[latex]\frac{20~\bcancel{sec}}{1}[/latex] x [latex]\frac{1~\bcancel{min}}{60~\bcancel{sec}}[/latex] x [latex]\frac{1~hr}{60~\bcancel{min}}[/latex] hr = [latex]\frac{20}{3600}[/latex] hr = [latex]\frac{1}{180}[/latex] hr

2) Now we can multiply by the 15 miles/hr

[latex]\frac{1~\bcancel{hr}}{180}[/latex] x [latex]\frac{15~mi}{1~\bcancel{hr}}[/latex] = [latex]\frac{15}{180}[/latex] miles = [latex]\frac{1}{12}[/latex] miles

3) Now we can convert to feet.

[latex]\frac{1~\bcancel{mile}}{12}[/latex] x [latex]\frac{5280}{1~\bcancel{mile}}[/latex] = [latex]\frac{5280}{12}[/latex] ft = 440 ft

4) Note we could have also done this entire calculation in one long set of products:

[latex]\frac{20~\bcancel{sec}}{1}[/latex] x [latex]\frac{1~\bcancel{min}}{60~\bcancel{sec}}[/latex] x [latex]\frac{1~\bcancel{hr}}{60~\bcancel{min}}[/latex] x [latex]\frac{15~\bcancel{miles}}{1~\bcancel{hr}}[/latex] x [latex]\frac{5280~ft}{1~\bcancel{mile}}[/latex] = [latex]\frac{20~x~15~x~5280}{60~x~60}[/latex] ft = 440 ft

Answer: The bicycle covers 440 feet in 20 seconds.

Example 22

You are walking through a hardware store and notice two sales on tubing.

  • 3 yards of Tubing A costs $5.49.
  • Tubing B sells for $1.88 for 2 feet.

Either tubing is acceptable for your project. Which tubing is less expensive?

Solution: State your givens and your goal.

Given: 3 yards of Tubing A costs $5.49. Tubing B sells for $1.88 for 2 feet.

Goal: Which tubing is less expensive?

1) Find the unit price per yard for each tubing. This will make it easier to compare.

Tubing A: 3 yards for $5.49

Unit price per yard: [latex]\frac{$5.49}{3~yds}[/latex] = [latex]\frac{5.49}{3}[/latex] [latex]\frac{dollars}{yards}[/latex] = $1.83 per yard

Tubing B: 2 feet for $1.88

2) Compare prices for 1 yard of each tubing.

Tubing A: $1.83 per yard

Tubing B: $2.82 per yard

Answer: Tubing A is less expensive than Tubing B.

Example 23

The cost of gasoline in Arizona is about $2.05 per gallon. When you travel over the border into Mexico, gasoline costs 14.81 pesos per liter. Where is gasoline more expensive? (Note: This problem requires a currency conversion factor. Currency conversions are constantly
changing, but at the time of print $1 = 18.68 pesos.)

Solution: State your givens and your goal.

Given: Gasoline in Arizona is about $2.05 per gallon. Gasoline in Mexico costs 14.81 pesos per liter. $1 = 18.68 pesos

Goal: Where is gasoline more expensive?

1) We will convert the Arizona price from dollars to pesos and gallons to liters to obtain pesos per liter.

[latex]\frac{$2.05}{1~gallon}[/latex] x [latex]\frac{18.68~pesos}{$1}[/latex] x [latex]\frac{1~gallon}{3.8~L}[/latex] = [latex]\frac{2.05~x~18.68}{3.8~L}[/latex] [latex]\frac{pesos}{L}[/latex] = 10.08 pesos per liter

2) Compare the pesos per liter values.

Arizona: 10.08 pesos per liter
Mexico: 14.81 pesos per liter

Answer: Gasoline is more expensive in Mexico.

Section 1.6 You Try Problem

Find the following unit rates for 6 pounds for $5.29. If necessary, round your answers to the nearest hundredth.
A) In dollars per pound
B) In pounds per dollar

UNIT 1 – Answers to You Try Problems

$0.88 per pound, 1.13 pounds per dollar

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MAT112 Mathematical Concepts & Applications Copyright © by Leah Polanski. All Rights Reserved.